I`ve wrote line below in my page $image1 is an output of a function which show an imageT but when I used it the image was shown in IE but not in firefox.
please guid me, thanks a lot.
echo ''
Posted by maniondagger, 12-09-2010, 05:47 AM
What if use the following
?
Posted by AndrisE, 12-09-2010, 07:11 AM
If you need button based on image, i recommend using and style it with CSS. You can remove default borders, paddings, margins, background and set your background image.
